2x+12=x^2-6x+28

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Solution for 2x+12=x^2-6x+28 equation: 



2x+12=x^2-6x+28

We move all terms to the left:

2x+12-(x^2-6x+28)=0

We get rid of parentheses

-x^2+2x+6x-28+12=0

We add all the numbers together, and all the variables

-1x^2+8x-16=0

a = -1; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-2}=+4$

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